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Pythagoras, the famous Greek philosopher, lived about 572 B.C. to 501 B.C. He proved the relation between the lengths of the sides of a triangle, Although, this theorem was known to the Babylonians 1000 years ealier, but, Pythagoras is believed to have the first to discovered a proof of this theorem. However, long ago ( 800 B.C.), the Indian mathe,atician Baudhaya had stated and proved this property of a right angled triangle.
Let us have a look at the fig. is a right triangle, right angled at C, so that AB is the hypotenuse and AC and BC are the sides of the right triangle,
Then,
i.e.,
Given: A triangle ABC right angled at B To Prove: Construction: From B draw BD Proof: Since BD
Now
Adding Eq (1) and (2) Hence Proved |
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Example 1: The lengths of two sides of a right triangle are 5 cm and 12 cm. Find the length of the hypotenuse.
Solution: Suppose BC = 5cm and AC = 12 cm.
By Pythagoras theorem,
Length of the hypotenuse = 13 cm.
Converse of Pythagoras Theorem:
THeorem: In a triangle if the square of one side is equal to the sum of squares of the other two sides, then the angle opposite to the first side is a right angle.
Given: A triangle ABC such that To Prove : Construction : Construct a triangle DEF such that DE= AB, EF= BC and Proof: Since Since DE = AB and EF = BC replacing them in the above equation But DF = AC Now in AB = DE [By Construction] BC= EF [By Construction ] DF = AC [Proved Above]
Hence | ![]() |
Illustration: ABC is an isosceles triangle with Ac = BC. If . Prove that ABC is aright triangle.
In AC = BC and Now Adding But From Converse of Pythagoras Theorem we can say that Triangle ABC is a right angled at C | ![]() |
A man goes 150 m due east and then 200 m due north. How far is he from the starting point?
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| Right Option : B | |||
| View Explanation | |||
The hypotenuse of a right triangle is 37 cm long. If one of the remaining two sides is 12 cm in length, then the length of the other side is | |||
| Right Option : A | |||
| View Explanation | |||
In fig. length of AE is ________________ | |||
| Right Option : C | |||
| View Explanation | |||
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